# Capacitors in Series

- The charge is always the same for capacitors in series.
- Turn series capacitors into an equivalent capacitor like so:

- These are eg. C1, C2, and C3
- Changing them into CEquivalent like so:

1 / C

_{Equiv}= 1/C1 + 1/C2 + 1/C3 + ….

- The sum of the voltages across capacitors in series will equal the voltage of the battery

To calculate the voltage of capacitors:

Voltage across the capacitor (V) = Charge stored on a capacitor (Q) / Capacitance (C)

V = Q / C

- Q will remain constant in a series
- C depends on the capacitor

- For the above image: Q/C1 + Q/C2 + Q/C3 = V (battery)
- Therefore: Q (1/C1 + 1/C2 + 1/C3) = V (battery)
- Finally we can deduce

1/C1 + 1/C2 + 1/C3 = V/Q = 1 / C

_{Equivalent}