Capacitors in Series
- The charge is always the same for capacitors in series.
- Turn series capacitors into an equivalent capacitor like so:
- These are eg. C1, C2, and C3
- Changing them into CEquivalent like so:
1 / CEquiv = 1/C1 + 1/C2 + 1/C3 + ….
- The sum of the voltages across capacitors in series will equal the voltage of the battery
To calculate the voltage of capacitors:
Voltage across the capacitor (V) = Charge stored on a capacitor (Q) / Capacitance (C)
V = Q / C
- Q will remain constant in a series
- C depends on the capacitor
- For the above image: Q/C1 + Q/C2 + Q/C3 = V (battery)
- Therefore: Q (1/C1 + 1/C2 + 1/C3) = V (battery)
- Finally we can deduce
1/C1 + 1/C2 + 1/C3 = V/Q = 1 / CEquivalent