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Capacitors in Parallel

  • Voltage remains the same
  • Equivalent Capacitance = C1 + C2 + C3 ….

  • C = Q / V
  • For A:
    • 3 = Q / 8
    • Q = 24
  • For B:
    • 6 = Q / 8
    • Q = 48
  • So C1 (24) + C2 (48) = 72C (equiv)
  • Ceq = 6F + 3F = 9F
  • Capacitor A has twice the Farad (F) –> therefore twice the charge


 

The above is the equivalent to:

  • C = Q / V
  • 9F = Q / 8V
  • Q = 72C

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