# Capacitors in Parallel

- Voltage remains the same
- Equivalent Capacitance = C1 + C2 + C3 ….

- C = Q / V
- For A:
- 3 = Q / 8
- Q = 24

- For B:
- 6 = Q / 8
- Q = 48

- So C1 (24) + C2 (48) = 72C (equiv)
- C
_{eq}= 6F + 3F = 9F - Capacitor A has twice the Farad (F) –> therefore twice the charge

**The above is the equivalent to:**

- C = Q / V
- 9F = Q / 8V
- Q = 72C